# What Is The Liquid Depth Inside The Tank?

I know that $$P_{total}=P_{gauge}+P_{atmosphere}$$, so $$P_{gauge}=P_{atmosphere}-P_{total}$$

$$P_{atmosphere}=101.325 KPa$$ and $$P_{gauge}=0.2 psig=1.38 KPa$$.

$$P_{gauge}=(0.8 \times sin{30})(900)(9.807) - (900)(9.807)(h)=1.38 KPa$$

This implies that $$h=0.4m$$, however the answer is $$0.24m$$.

$$1.38/101.325*1000/900=0.01513 \\ 40-15.13= 24.8cm$$