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I am currently studying engineering thermodynamics from Cengel and Boles and there it is given that total energy of non flowing fluid per unit mass basis is given as $e=u+\frac{v^2}{2}+gz$.But if the fluid is non flowing how can it have macroscopic kinetic energy$\frac{v^2}{2}$?

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  • $\begingroup$ Does Cengel & Boles say the fluid is moving or stationary? Or is the expression given to cover all conditions and you have to make the correct assumptions? $\endgroup$
    – Solar Mike
    Jul 25 '19 at 19:09
  • $\begingroup$ That's is the definition of the specific energy. Depends on the thermodynamic conditions one or more parameter can take zero value. $\endgroup$ Jul 25 '19 at 20:20
  • $\begingroup$ "... the total energy of a flowing fluid …" "But if the fluid is non flowing ..." - see your problem there? But if the fluid is not flowing, $v = 0$ and its macroscopic kinetic energy per unit mass is $v^2/2 = 0$. So what exactly is the difficulty? $\endgroup$
    – alephzero
    Jul 25 '19 at 22:25
  • $\begingroup$ @alephzero It was a typo.That was given as energy of a non flowing fluid.I can upload the snapshot but it may violate copyright laws. $\endgroup$ Jul 26 '19 at 4:55
  • $\begingroup$ @AtulGautam uploading an image of that particular part will not violate copyright, but if you upload the whole book then you may well have an issue... The are hundreds of questions with snapshots of particular formulae, expressions, questions and diagrams on here.... $\endgroup$
    – Solar Mike
    Jul 26 '19 at 7:38
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A non-flowing fluid can have kinetic energy if it is moving as a rigid body. For example, a full water bottle (no room for flow inside) is thrown through the air without rotation.

However, this is not likely the intent of the author for this situation.

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  • $\begingroup$ This is coordinate dependent. If the coordinate system is stationary with respect to the controle volume, then yes your answer is applicable. If we choose the coordinate system attached to the CV, then the kinetic energy is zero. $\endgroup$ Jul 26 '19 at 13:12
  • $\begingroup$ Yes of course, but the question was how can it happen. $\endgroup$
    – N. Morgan
    Jul 26 '19 at 17:39

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