If you have a look at the car's wheels, you'll notice that they have holes which can be of different forms (mostly circular or rectangular).
Why do they have such holes? Doesn't that reduce the stiffness of the wheels?
If you have a look at the car's wheels, you'll notice that they have holes which can be of different forms (mostly circular or rectangular).
Why do they have such holes? Doesn't that reduce the stiffness of the wheels?
Car wheels have holes mostly due to weight and cost considerations. Each hole is a chunk of material that you aren't wasting and weighing down the wheel with.
As another bonus, the holes help with cooling the brakes by allowing airflow between the inside and outside.
The shape and size of the holes are calculated to have a minimal impact on the structural integrity of the wheel.
Many of the answers so far have mentioned that part of the purpose of the holes is weight reduction, but most of them don't express why weight reduction in the wheels is important. There are two major reasons; the first (also mentioned by Steve Ives) is that the suspension systems in vehicles operate better if the 'unsprung' mass is kept as low as possible, and the second (not mentioned so far) is that shaving weight from the wheels contributes more significantly to performance than shaving weight from the rest of the vehicle.
To see why this is true, consider the energy that the engine must put into the vehicle to get it moving at a speed $v$: $$ E=\frac12 m_tv^2+\frac12 I\omega^2 $$ For the wheels we can express the angular velocity in terms of the linear velocity as $\omega=\frac{v}{r}$ where $r$ is the radius of the wheel. The moment of inertia of the wheel can be expressed as $I=\eta\ m_dr^2$ where $m_d$ is the mass of the wheel. Here $\eta$ is a number between $\frac12$ and 1, but is closer to 1 since a wheel is closer to a thin hoop than a solid disk. Sticking all of this back in gives $$ \begin{align} E&=\frac12 m_tv^2+\frac12\eta\ m_dr^2\frac{v^2}{r^2}\\ &=\frac12 (m_s+m_d)v^2+\frac12\eta\ m_dv^2\\ &=\frac12[m_s+(1+\eta)m_d]v^2, \end{align} $$ where I have used $m_s$ as the non-rotating mass of the vehicle. So, you can see that shaving mass from the wheels is equivalent to shaving a factor of $1+\eta\simeq 2$ as much mass from the non-rotating parts of the car.
There is an additional, relatively minor, effect due to angular momentum for which it is advantageous to reduce the weight of the wheels. Due to conservation of angular momentum, the body of the car will tend to roll toward the outside of a turn when the wheels are rotated to initiate the turn. Reducing the moment of inertia of the wheels reduces their angular momentum and thereby reduces the amount of body roll upon steering.
Mainly to reduce weight. A car's handling characteristics are improved by keeping the 'unsprung weight' (the weight of the car not isolated from the ground by springs i.e. the wheels, axles, hubs, brake disks, calipers, etc.) as low as possible. Holes in the wheels reduce this weight.
The lower weight helps the unsprung portions of the car to follow the bumps and dips of the road more closely.
The holes in wheels serve a few purposes. They reduce the weight of the wheel itself, although not by much. The holes in those particular wheels actually appear to be adding rigidity and strength to the wheel. The extra folds in the steel make it stronger than if it was just flat. The holes may also help prevent the build up of brake dust. I believe Ratchet Freak is correct about airflow.
It's for airflow to allow for extra cooling. In most situations, that extra airflow isn't going to help. But when you're doing heavy braking coming off of a mountain, it can make the difference between your being able to brake and your brakes failing from over-heating.
Yes I agree, the "moment of inertia" is a factor in making "spoked" wheels, the holes in pressed wheels will reduce weight, and allow circulation.
The truth is, for this kind of wheel, it is largely cosmetic. It also makes them easier to manually handle (finger holes).
For this type of wheel it would not make a lot of difference if they were not there. But even if they were discs milled from billet magnesium alloy they can be a lot thinner between the hub and the rims, in the same way an I-beam profile is thinner than a square beam.