Can you please help me find the answer to the above question, I am unsure how to work with F2 as I can't find the distance from Moment A or Moment J to this. Thank you
2 Answers
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Welcome to Engineering! Have you considered that the force $F2$ has a component in the $x$ and the $y$ direction? If you break $F2$ down this way, you can observe that you now have a perpendicular distance to each of these components that you can use so sum the moments about one of the hinges.
If you sum the moments about the hinge $A$ you should only have one variable which is the horizontal support reaction at $J$.
You can then take that reaction into the sum of the forces to maintain equilibrium.
This is a conceptual guide to solving your problem, if you have any more specific issues I think it would be appropriate for you to show your work, and your issue here.
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Whenever confused start from the basics: $$\begin{align} \sum M &=0 \\ \sum F_x &=0 \\ \sum F_y &=0 \end{align}$$
Therefore $$ F_{a_y} = F_1 + F_2 \cos30= 1.5 + 2.598 = 4.09\text{ kN (up)}$$
J has no vertical reaction.
As for the moment sum we have: $$\sum M =0 \therefore F_{j,x}\cdot4 - (1.5\cdot2 + 2.598\cdot6 -3\cdot1/2\cdot2) =0$$
The last part in the parenthesis is the horizontal component of $F_2$ multiplied by its moment arm to get its contributory moment about A.
From here you can calculate horizontal reaction of J and then the horizontal reaction of A.
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$\begingroup$ I'd just make it explicitly clear that the $1/2$ in the moment sum is actually $\sin(30)$. $\endgroup$– WasabiCommented May 11, 2019 at 15:18