# Torque required to launch a tennis ball

I am trying to find out if the 12 V DC electric motors that I have are powerful enough to launch a 100 g tennis ball 30 m away. The tennis ball is put down a pipe and ends up wedged in between 2 wheels (radius = 0.05 m) driven by the two 12 V DC electric motors. The picture below should hopefully clarify the situation: • The electric motors are spinning at ~7000 RPM (no load), the motor specs are here: http://www.banebots.com/product/M5-RS555-12.html
• A wheel (with mass of 0.05 kg and radius of 50 mm) is connected to each motor
• The tennis ball is dropped down the pipe and ends up in between the two rotating disks
• The launching angle is 20 degrees

I calculated how far the ball flies if I keep the RPM constant based on the horizontal component of the linear velocity in combination with the flying time and launching angle. However, this does not account for the mass of the tennis ball.

When the ball passes through the two wheels, the electric motors will see an opposite moment. I guess I can calculate the moment by multiplying the mass * g * radius. However, it is not clear to me how I can then accurately calculate the effect on the RPM of the motors. I can optimize the location of wheels so that the ball isn't squeezed too much, so I was hoping to ignore this in the calculation and build in some margin instead. In the end, I would like the ball to fly at least 30 m.

Does anybody have an idea on how I can calculate if the motors are strong enough to launch the ball 30 m away?

• I very strongly doubt that any reasonble propulsion system can launch a tennis ball 30 m, because the ball has low density, high drag, and atmospheric effects will limit the range. Meanwhile, what you've drawn is a standard launcher used for baseball hitting practice. Take a look at the specs for commercial items. – Carl Witthoft Dec 17 '18 at 18:57
• @Feijo What specifications of motor did you go for in the end and how did they perform? – mrswadge May 17 '19 at 11:21