1
$\begingroup$

A motor is used to drive a shaft that is geared through 1:1 bevel gears to a propeller. The shafts are mounted on bearings in a hard casing that is attached to a 2nd ground. I want to know if the 2nd ground needs to react any of the torque produced by the motor, to stop the whole casing rotating? If so, how much? Any help would be greatly appreciated. I have tried sketching the system below for clarity.

Many thanks

Propeller Torque System

Improve this question
$\endgroup$
3
  • $\begingroup$ What have you considered? $\endgroup$
    – Solar Mike
    Nov 5, 2018 at 12:07
  • $\begingroup$ No. The bearing on the shafts is ideally frictionless without direct contact with the shafts in order not to impede the rotation, but will prevent undesirable vibration. The bearing will be short-lived if stay in gapless contact with the shafts. Any force on the casing will be resisted by ground 2 though. (Note, I am no a mechanical engineer) $\endgroup$
    – r13
    Aug 23, 2021 at 17:50
  • $\begingroup$ To clarify my comment above, ground 2 shouldn't feel any torque unless the casing will twist, which defeats the purpose. Similarly, ground 1 shouldn't feel torque unless the casing of the motor will twist. $\endgroup$
    – r13
    Aug 23, 2021 at 18:04

2 Answers 2

Reset to default
0
$\begingroup$

Yes it has to react.

Say your engine can generate a maximum of 150 Lb-Ft torque. And you attach to the ground or back of a boat by a bracket which has 2 bolts on 16 (1.33 Ft) inches apart.

your bracket has to be able to resist the:

150 Lb- Ft/1.33 Ft = 112.78 Lb,

pull out tension on one bolt and push in compression on the other one.

Improve this answer
$\endgroup$
0
$\begingroup$

Yes, it does.

Imagine you block the propeller entirely, say, fuse it to the casing, or tangle it in a huge wad of fishing net that causes huge drag (or instead, just fuse the two gears together, so they can't turn - oh, say, put a wrench between them.) In this case the motor, through the shaft and its bevel gear will try to spin the entire assembly of the propeller, its shaft, its two bearings, the lower bevel gear and the entire casing, making the whole thing turn around the motor shaft.

Ground2 is what prevents that and causes the torque to be transferred to spinning the propeller as opposed to spinning the entire assembly. It doesn't 'feel' much torque

the gears and the propeller. The upper two bearings are negligible, as they only transfer as much torque as their internal friction. But any torque put by environment on the propeller will be applied to the gear, and transferred to ground2 through the two lower bearings.

There will be some extra torque from friction of two upper bearings and the bevel gears, but that's just losses, as opposed to torque from the work done. I believe the torque will distribute equally between the two grounds, assuming ground 2 surrounds the casing instead of just being attached to one edge.

Improve this answer
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.