# RF energy intensity after reflection

Intensity of RF wave at a distance from source can be calculated by using inverse square law. But imagine an RF energy travels a distance $d1$ before being perfectly reflected from a metal surface. How much is the energy intensity at a point B, which is at a distance $d2$ from the point of reflection?

1) B lies in the line of reflection.

2) B is not located at the line of reflection. It forms an angle $\theta$ with the line of reflection.

My though process is following. Intensity must be much more along line of reflection. Probably , it should follow inverse square law along line of reflection, but i am not sure.

• I'm curios to see your calculations, could please provide them ? Aug 31 '18 at 16:06
• If the Point B is between the source and the mirror, are you assuming that the detector casts a shadow on the mirror? Aug 31 '18 at 16:58
• Do you have any background in basic optics? because this is just putting a mirror in the system, thus folding the propogation path. Nothing else changes. Aug 31 '18 at 18:32
• ^In some cases, adding a mirror at the correct location and angle can redirect 'overspill' back to the detector, and increase the intensity of radiation at that point. Aug 31 '18 at 19:46