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I'm designing a rolling machine for reduction of steel ingots of $5 mm$ to $1.96 mm$ thick. I can convince myself using equations why increasing the coefficient of friction (in case of lubrication system fails) results in evenly distributed load in rolling machines, but i can't describe intuitively why this happens. enter image description here

As the friction coefficient increase, normal forces increase as wel and i expect the peak to move upward, but why it moves to the right as well ?

The horizontal axis, represents the angle of contact zone, and the vertical axis shows the dimensionless stress. $\frac{\theta}{\theta_0} = 0$ means exit angle(reduced) and $\frac{\theta}{\theta_0} = 1$ means entry angle.

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    $\begingroup$ Could it be that with the increase in friction, your increasing some form of deflection in the machine, resulting in a change of angle? $\endgroup$
    – Corey
    Aug 20, 2018 at 14:30
  • $\begingroup$ @Corey, interesting idea, indeed, increasing the normal force results in deflection of the slab and it increases the contact surface. $\endgroup$
    – user14407
    Aug 20, 2018 at 14:47

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