I found this gif, and I was wondering how much force is applied on the pin due to the spring from the top? Also, is there an industry standard for the amount of force exerted?
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The force of applied by the spring to the pin, will depend on how much the spring is compressed. This can be calculated by using Hooke's Law:
Finding k (Using assumptions)
In order to find find k, for demonstration we will just assume a few properties of the spring based on what we can see in the gif.
k = 0.136 N/mm
Finding X maximum
For demonstration we will use 3 mm for the maximum compression of the spring.
Calculating Maximum Force From Spring
Using the assumed properties and plugging them into Hooke's Law.
F = k X
F = (0.136)*(3)
F = 0.408 N
This type of lock is a Tumbler Lock and the spring force is most likely not regulated or standardized in industry, but other contributors may have more information.