# How much force does a lock's pin have due to the spring?

I found this gif, and I was wondering how much force is applied on the pin due to the spring from the top? Also, is there an industry standard for the amount of force exerted? • You know the more the pin deflects the higher the spring force. So there isn't a constant value, but there is a max value depending on the width of the key. Apr 7 '15 at 21:02

Hooke's Law

The force of applied by the spring to the pin, will depend on how much the spring is compressed. This can be calculated by using Hooke's Law: Finding k (Using assumptions)

In order to find find k, for demonstration we will just assume a few properties of the spring based on what we can see in the gif.

Spring Constant Calculator k = 0.136 N/mm

Finding X maximum

For demonstration we will use 3 mm for the maximum compression of the spring.

Calculating Maximum Force From Spring

Using the assumed properties and plugging them into Hooke's Law.

F = k X

F = (0.136)*(3)

F = 0.408 N

Industry Standards

This type of lock is a Tumbler Lock and the spring force is most likely not regulated or standardized in industry, but other contributors may have more information.