0
$\begingroup$

I currently have this load cell, which has a 10V excitation voltage. However, there is a very nice/convenient load cell amplifier that works with an excitation voltage of 5 VDC.

What are the consequences of operating a cell at a voltage lower than the normal excitation? Just increased noise in the signal?

$\endgroup$
1
$\begingroup$

The load cell you linked to has a line item on the specs that says "Output: 2 mV/V nominal". Let's just say that you picked the version with 100 lbf full scale output. What that means is this: if you use a 1 V excitation, you'll get a response something like this

Load    Output
  0 lbf   0 mV
 50 lbf   1 mV
100 lbf   2 mV

Now if you use a 10 V excitation, you'll get this

Load    Output
  0 lbf   0 mV
 50 lbf  10 mV
100 lbf  20 mV

So if you want to use a 5V excitation, it will work perfectly fine. Just do the math on the expected output.

Regarding your comment on noise. The signal to noise ratio will be likely be better with a higher excitation voltage. So yes, if you use 5 V instead of 10V, you probably have a slightly worse signal to noise ratio. Depends on your application and the precision required as to whether that will be acceptable.

$\endgroup$
2
  • $\begingroup$ So given that, this product works fine for my purpose? I'm having trouble navigating the selection process for hooking up a load cell to a pc correctly, so a catch all system (while probably suboptimal) may meet my needs... $\endgroup$
    – User2341
    Aug 12 '18 at 22:58
  • $\begingroup$ I have not used that particular product, but it looks like it should work. $\endgroup$
    – Daniel K
    Aug 13 '18 at 1:41

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.