# Linear actuator on a scissor lifting table

I am designing a scissor lifting table and I have an issue with the linear actuator. This table should be lifting 100 kg. I studied the problem in two ways : a static study and a power study. My table is a 3-level table. Here is a schema of a one level table : (1) and (4) are V-rails that guide wheels on points A and F. (5) is the linear actuator. (2) and (3) are scissors, and all the mechanical connections between the different parts are pivots (revolute).

In this static study, I found (page 3) that the two linear actuators have to lift a load of minimum 2158.2 N. So each linear actuator has to be lifting 1079.1N.

In this power study, I found (page 2) that the two linear actuators have to lift 12988 N (6494 N without the safety factor). So each linear actuator has to be lifting 6494 N (3247 N without the safety factor).

Between the two results, I have a ratio of 3. I guess the second study is false, but I'm struggling finding why, and I still have no solution...

I hope you can help me, and I thank you for your time :)

Muthu

• 3 is the number of scissor links, which is likely related Aug 1 '18 at 14:41
• You should really typeset your calculations, or better yet calculate in a software and have it typeset your stuff. Aug 1 '18 at 15:37

Hence the demand on actuator is $\space =\frac {( F\times AC)}{BC}$
By roughly scaling your sketch the force on actuator is $= 100\times 9.8 \times 5/2 = 2450 N$