0
$\begingroup$

NPSHa formula - h(sp) +/- h(s) - h(f) - h(vp)

h(sp)- static pressure head (absolute) applied to the fluid

h(s)- elevation difference between fluid level in reservoir to pump inlet

h(f) - friction loss in suction piping

h(vp)- cap or pressure of the liquid at a stated temperature

How do I determine whether h(s) is a positive or negative ?

I’ve researched that-

Pump below reservoir , h(s) is a positive and vice versa but I don’t know the reason behind it ... I’ve been told that if it’s not good for the pump, u have to substract away from the NPSHa formula which makes sense for h(f) and h(vp). and if it’s good for the pump, you have to add.

am I right to say it’s because the fluid loses more energy as it needs to fight against gravity , that is why h(s) is negative if the pump is above the reservoir, this means more work for the pump.

and if pump is below reservoir, the fluid doesn’t lose much energy.

$\endgroup$
  • $\begingroup$ I don't understand the question as stated. However a liquid pump must have a positive NPSH to operate properly . Otherwise , cavitation is likely which seriously deteriorates the pump performance. and may damage it There are special cases like a jet ( boost) pump that appear not to conform . $\endgroup$ – blacksmith37 Jul 28 '18 at 17:14
1
$\begingroup$

The reason h(s) is positive when the pump is below the reservoir fluid level is that there is a pressure created by the height difference which contributes to the net work done.

When the pump is above the fluid level, then the pump has to apply work to get the fluid into the pump before delivering on it so that work reduces the net work done.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.