0
$\begingroup$

I had a PC Mountable Wet/Wet Differential Pressure Sensor I used it to measure a pressure difference , I don't know how to convert its output to pressure !

$\endgroup$
1
  • 3
    $\begingroup$ How is this not directly answered in the datasheet? $\endgroup$ Mar 31 '15 at 14:27
1
$\begingroup$

Well, it looks like your sensor is +/-5psid (based on the link you provided), so looking at the datasheet, we have (assuming a 10VDC excitation) 16.7mV at 1psi and 50mv at 5psi. Assuming the sensor is linear (the datasheet states that linearity is +/-0.25% of full scale), you have the following relationship:

P = V * 0.1201 - 1.006

Where P is expressed in psi and V in mV. This does not take into account any possible hysteresis (0.2% of full scale according to the datasheet).

If you want an accurate reading, you should probably do your own calibration by applying a series of known pressures (measured with a calibrated instrument, e.g. manometer) and reading the sensor output.

EDIT

How did I arrive at the relationship? It's fairly easy, you're fitting a straight line to two points, so you're looking for a slope and an offset:

1psi = 16.7mV * slope + offset
5psi = 50mV * slope + offset

That's 2 linear equations with 2 unknowns (slope and offset), which is easily solved to give the values mentioned above. That's really basic maths though, I would expect any engineer or even technician to know how to do that, which is why I hadn't included the details on how to calculate the values in the first place.

$\endgroup$
0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.