My professor says, the internal hinge can not transfer moment:
But can we calculate $\Sigma M_A=0$ for whole beam ( without cutting it or something) this way?:
$\Sigma M_A=0 ===\Rightarrow M_A+(D_y \times 4m ) + 3KN.M =0$
with this equation we literally transferred the 3KN.M moment to point A while my professor says the internal hinge can not transfer moment.
Something is wrong, and I don't know what it is.