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diagram:

enter image description here

Assuming

1) the scanner can angle a beam anywhere on the circular off-axis mirror and

2) the off-axis mirror can be rotated as an the diagram to any angle needed,

can the beam shooting at any point on it from the scanner be made parallel to the middle beam bounced off of the off-axis mirror?

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No. The final mirror on the scanner has a smaller surface area than the 'rotating off-axis mirror'. Consequently, for a beam of light to hit near the edge of the larger mirror, it must be diverging from the centreline connecting the centre of those two mirrors. As the light paths are diverging, they will not be parallel after the off-axis mirror, unless that mirror is not flat.

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  • $\begingroup$ I need the beam orientation to be parallel, not the beams to be parallel in the sense of not diverging into each other. Sorry for being unclear. $\endgroup$ – Mark Legault Apr 4 '18 at 14:49
  • $\begingroup$ But I don't understand your point "The final mirror on the scanner has a smaller surface area than the 'rotating off-axis mirror'" $\endgroup$ – Mark Legault Apr 4 '18 at 14:50
  • $\begingroup$ I interpreted your question to mean "can the beam coming from the mirror (from any point - i.e. the point does not matter) be made parallel to the beam that is reflected from the centre of the mirror? Because the light is not collimated, the answer to that question is "No", If that's not the question you meant to ask, then please edit your question (and diagram) to be clearer. $\endgroup$ – Jonathan R Swift Apr 4 '18 at 22:19
  • $\begingroup$ collimation has nothing to do with whether a beam bouncing off of a flat mirror will be parallel or not to another beam bounced off at a different point. This is literally like adding a third very large scanner mirror to the setup. it's a tight beam but not a collimated laser-like beam with <1 mrad divergence. $\endgroup$ – Mark Legault Apr 4 '18 at 22:21
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Yes, but...

enter image description here

As you see, the outgoing part of the yellow beam is parallel to the reflected part of the red beam, just as you wished. But for that to happen, the galvo must be located in such a way that it will obscure a fragment of the reflected field - the green beam, reflected from the mirror, will strike the structure of the galvo, and the reflected image will have a big black blob of shadow of the galvo somewhere off to the side.

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  • $\begingroup$ not sure I understand why $\endgroup$ – Mark Legault Apr 4 '18 at 14:52
  • $\begingroup$ @MarkLegault: Angle of reflection is angle is equal to angle of incidence. If ray 1 (red) falls at angle x, reflected at same x, so the reflected part is at angle 2x from the incident part. Cast a ray 2 (yellow), at such an angle of incidence that it's equal to angle of reflection of the first. Its reflected part will be at -2x to the incident part. That means, in between them there exists a ray that falls - and is reflected - at angle zero, returning to the origin - hitting the galvo. $\endgroup$ – SF. Apr 4 '18 at 15:04
  • $\begingroup$ But why is in your illustraton the galvo at the height or in front of the off axis mirror and not out of its way like in mine? Not that my illustration is in any way good (liek the angle off the off-axis mirror) $\endgroup$ – Mark Legault Apr 4 '18 at 16:25
  • $\begingroup$ @MarkLegault: because the ray 2 would miss the mirror, simple. If you move it so that no normal to the mirror lies in line, it's not possible, period. $\endgroup$ – SF. Apr 6 '18 at 21:03

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