I am trying to ascertain the maximum line pull for an old winch I have in my workshop and I am arriving at values that are considerably higher than what is in the original manufacturer's manual. I am not sure if I am doing this right and want to validate my calculations.
The winch is rotated hydraulically with a motor. The motor shaft is connected to a wet brake which in turn is connected to a planetary gear hub. This hub is then connected directly to the drum.
If the motor builds up 3000 PSI and has 38 LPM of flow it produces a torque of 295Nm with 316RPM. (or 30.08163KGm)
The wet brake disengages and produces negligible friction.
The ratio in the gear hub is +53.58:1
The diameter of the drum on the winch is 0.81m
The diameter of the cable used to pull is 0.0202m
From what I understand, to find linear force for a winch I must use this formula: Torque = Force X Arm
Where Arm = radius of drum + radius of cable radius drum = 0.81m/2 = 0.405m radium cable = 0.0202m/2 = 0.0101m Arm = 0.405m + 0.0101m = 0.4151m
Where Torque = Torque of motor X ratio of gear hub Torque = 30.08163KGm X 53.58:1 = 1611.7737354KGm
Therefore Force = Torque / Arm Force = 1611.7737354KGm / 0.4151m = 3882.856505420381KG
Am I correct to therefore say that the maximum line pull before the winch stalls is 3882.85KG? Therefore We can say it can lift anything bellow this weight?