Given that momentum is the product of speed and weight (Velocity x Weight) would rapid deceleration or acceleration in weighless space, of Space X's BFR have an impact on its passengers. I ask because if it is to travel at 27000km/h most of its journey would be spent accelerating and decelerating very much limited by earthlike g forces as airliners do, therfore minimizing on the reduction of travel time. Would most of the braking and accelerating have to take place in space at zero gravity?
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$\begingroup$ Please begin by figuring out how long it takes to accelerate to 27000 km/h at 1 G acceleration. 1 G = 9.8 m/s or 35.3 km/h. Each second, you are going 35km/h faster. $\endgroup$– Phil SweetOct 3, 2017 at 21:28
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The factor here is mass, not weight - weight is the force produced by mass and the effect of gravity.
The same kinds of forces are produced by acceleration. In "weightless space" (zero gravity) a spacecraft accelerating at 1g (9.81 m/s2) will impose the same force on its occupants as earth's gravity.
For a high speed spacecraft, a lot of the time will be spent accelerating and decelerating to keep the force on the occupants within tolerable limits.
answered Oct 3, 2017 at 7:58
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$\begingroup$ I never considered before that constant acceleration at 1g for half the journey and -1g for the remainder would give a 1g environment for the occupants. Unfortunately this would not be very efficient and regenerative braking would not be an option! $\endgroup$ Oct 3, 2017 at 19:37