If i have that situation(from the picture below) i will need an acceleration=0.16m/s^2?
and a force F~=15N?
where r=radious of the wheel
and F i think that's the force that i need
if yes,i will need a torque of 0,036m*15=0.54Nm?
So,in that case,if i have a motor that has a torque=0.54Nm with a power output=150W will move the skate with a speed of 10m/s? With what i'm wrong??
I can calculate the torque of the motor with this
T = (I * V * E *60) / (rpm * 2pi)?
So in my case if i have a motor 270kv 1665W with Continuous current: 80A with 60%efficiency with a Lipo Battery 22.2V 10.4Ah 30C, I will get:
Power Input =22.2*10.4 =230.88W
Power Output =230.88*0.6=138.52W
So what speed the board will have??
With what i'm wrong?Please explain
How the diameter of the wheel affect the speed and acceleration?
if i have 72mm wheels,so 0.22m circumference with 5994 rpm will have 0.22*5994=1.318m/min? so 21.96m/s?? if i'm not wrong,how the mass affect that speed? and the not enought torque?
How the diameter of the pulley A and B and the number of teeths and the distance between the teeths affect the torque and speed?
How can i calculate the output torque and speed of the pulley A ??
With what i'm wrong,how i can calculate what i need please be patient i never take physics/engineering class i just searched on internet don't be annoyed with my calculus
Update: if i have torque=rm(v/t) i will get v=(timetorque)/(rm),in my case v=(60*0.21)/(0.036*90)=3.88m/s?? It's that right? If i get more torque with the pulleys from the motor to the wheel i can get something like 7m/s?
Ok Update2: i have 2 gears ,one with 27T other with 14T ,i founded that the ratio is 27/14=1.92 so the torque is 0.21*1.92=0.4Nm? and the speed will be 5994/1.92=3121RPM?
If yes,i will have v=(timetorque)/(rm) V= 7.4m/s? i can't understand what i'm doing wrong..
Maybe if i think that i have enought torque to move the board,and if the wheel rotate with 3121rpm and 72mm diameter with 0.22m circumference,it will make 0.22m each rpm so 3121*0.22=686.62m/min=11.44m/s. What is the true ??#Please help !#
Update 3: if i will use a 36T pulley with a 14T pulley on the motor with 138.52W power output,5994RPM,0.21Nm torque,70mm wheels
and i need a torque=0.54Nm
i will have 36/14=2.57 ratio ,so 0.21*2.57=0.54Nm torque and 5994/2.57=2332RPM
so each min i will make 0.22m(circumference of the wheel)*2332rpm=513m/min=8.55m/s??