I'm stucked at trying to find the vertical reaction at top and bottom constraint, i know how to do the rest. Can you show me how?
First you should check if the truss is statically determinate. In one of your comments you said, that only the bottom support has a vertical reaction. I assumed that all members are joint-connected, thus are not able to transfer any moment.
There's a formula to determine, if a truss is statically determinate:
$$ n= r+s-2k $$
$r$ … number of support reactions $(3)$
$s$ … number of members $(7)$
$k$ … number of nodes $(5)$
$$ \to n=3+7-2\cdot5 =0$$ thus the truss is statically determinate, which means you can find the support reactions. $$ \sum H = A_H+B_H =0 $$ $$ \sum V= B_V =Q $$ $$ \sum M(B)=A_H\cdot a + Q\cdot b =0 \qquad \star$$ The $\star$-equation is the moment equation, which can be defined for any point, I chose to establish the moment equation with respect to point $B$, because the forces $B_H$ and $B_V$ do not produce any moment wrt point $B$, thus they cancel out. With these three equations you can solve for all three support reactions and then find the member reactions.
No load can be in the far left member as it is supported at both ends. Axial force is directly proportional to change in length; if there can be no change in length (due to both ends being fixed in position) then there can be no axial force.
Therefore resolving vertically at the top support, the vertical reaction is equal to the shear in the horizontal member. If we're assuming axial loads only for truss behaviour, then there is no shear and hence no vertical reaction
Therefore the whole vertical reaction is taken by the lower support