I want to mount two patio heaters on my terrace in front of a window wall. I cannot attach anything directly to the window wall so I am going to run an aluminium box beam between two brick columns. The beam will be 5000mm long. The beam dimensions are 80mm x 40mm with a 4mm thick wall, 13kg in weight. The heaters weigh 6.5kg each and are 1000mm long. They will be 1000mm from each end and therefore 1000 from each other. I need to drill 8 x 8mm holes for mounting brackets (2 brackets per heater, 2 holes per bracket).
Using the 5th equation from the bottom the displacement is:
disp = Wa^3b^3/3EIL^3
We can superimpose it for each of your loads. Essentially your beam is loaded with 3.25kg (~33N) at 4 points (1,2,3,4m along).
I.e. disp(total) = disp(1st load) + disp(2nd load) ... + disp(4rth load)
For all the loads W = 33N
for the first and fourth a = 1 and b = 4 for the second and third a = 2 and b = 3
E = 69 x 10^9 (Elastic Modulus of Aluminium)
I = 7.11x10^-7 (Second moment of Area)
Ends up being:
disp = 0.001m
So at the middle x = 2.5
So displacement = 0.0025m
Sounds like it should be fine.