The problem given is as follows:

A Carnot cycle has a heat engine fluid efficiency of 30%. The heat transfer to the fluid in the boiler Qh happens at 270 centigrade. At 270 centigrade, the entropy of saturated vapour and liquid water are 6.001KJ/(kgK) and 3.067KJ/(kgK), respectively. Determine the net work produced by the Carnot engine.

I am pretty sure to solve it you need to use the Carnot efficiency equation so 0.30 = W / Qh but I am not too sure how to get Qh from the information provided. Please explain or put me on the right track if you can!

Thank you in advance!


Assuming reversible heat addition process: $$q = \int_{s_1}^{s_2} T \,ds = T \int_{s_1}^{s_2}ds=T\Delta s $$ $$ w = \eta_{carnot} \,q$$


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.