# Lifting 250 watts of heat using some heat exchanger/heat sink [closed]

I am new to thermal management.

I want to lift about 250 W of heat from hot end of thermoelectric cooler/peltier cooler (TEC).

The temperature of hot side of TEC is 30°C.

I want to use some kind of heat exchanger/chiller to accomplish this task.

I am using equation

$$P = h S (T_s-T_f)$$ where

$P$ = heat to be removed = 250 W

$h$ = heat transfer coefficient

$S$ = area of contact between hot side of TEC & fluid (air/water) used for convective heat transfer

$T_s$ = temperature of hot end

$T_f$ = temperature of fluid (air/water)

I do not know how to calculate $h$. If I calculate that, it will give me temperature of fluid.

How do I compute $h$?

And is my approach correct?

• I might be asking a silly question, but the hot end is 30 C? I think it would take a large heatsink to dissipate 250 watts from such a small temperature difference. I haven't used peltier, etc. coolers myself but I would expect a regular semiconductor device to be a lot hotter. I'd then size a heatsink based on the difference between the desired device temperature and the surrounding air. – Andy Oct 6 '16 at 11:03
• You've left out the flow rate of your coolant, for one thing. Are you intending for passive flow, or using a fan/pump? There's a lot more design info required. – Carl Witthoft Oct 6 '16 at 13:02
• @CarlWitthoft: I am using water as coolant; and a pump. Let us assume flow rate of water is 4 liters/minute. – atom Oct 10 '16 at 3:57