Lifting 250 watts of heat using some heat exchanger/heat sink [closed]

I am new to thermal management.

I want to lift about 250 W of heat from hot end of thermoelectric cooler/peltier cooler (TEC).

The temperature of hot side of TEC is 30°C.

I want to use some kind of heat exchanger/chiller to accomplish this task.

I am using equation

$$P = h S (T_s-T_f)$$ where

$P$ = heat to be removed = 250 W

$h$ = heat transfer coefficient

$S$ = area of contact between hot side of TEC & fluid (air/water) used for convective heat transfer

$T_s$ = temperature of hot end

$T_f$ = temperature of fluid (air/water)

I do not know how to calculate $h$. If I calculate that, it will give me temperature of fluid.

How do I compute $h$?

And is my approach correct?

closed as too broad by Carl Witthoft, Wasabi♦, Fred, hazzey♦, Dave TweedOct 8 '16 at 20:06

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

• I might be asking a silly question, but the hot end is 30 C? I think it would take a large heatsink to dissipate 250 watts from such a small temperature difference. I haven't used peltier, etc. coolers myself but I would expect a regular semiconductor device to be a lot hotter. I'd then size a heatsink based on the difference between the desired device temperature and the surrounding air. – Andy Oct 6 '16 at 11:03
• You've left out the flow rate of your coolant, for one thing. Are you intending for passive flow, or using a fan/pump? There's a lot more design info required. – Carl Witthoft Oct 6 '16 at 13:02
• @CarlWitthoft: I am using water as coolant; and a pump. Let us assume flow rate of water is 4 liters/minute. – atom Oct 10 '16 at 3:57