0
$\begingroup$

A bar of length L and of uniform cross-section area A and second moment of area 1 is subjected to pull P.If the young's modulus of elasticity of the bar material is E,the expression for strain energy stored in the bar will be 1)P2L2/2AE 2)PL2/2EI 3)PL2/AE 4)P2L/AE

(Note:The P2L2 and 2AE in the option is P squared,L squared and 2 times AE respectively)

$\endgroup$
1
$\begingroup$

5) None of the above.

The strain energy stored in the bar will be $$U = \frac{1}{2}P\Delta$$

where $$\Delta = \frac{PL}{AE}$$

or $$U=\frac{P^2L}{2AE}$$

See Strain Energy

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.