0
$\begingroup$

When doing pitot tube measurements, the pressure is measured in 2 places. At the wall (A), for the static pressure and against the flow (B), for dynamic pressure. Where the difference between these two is required to determine the velocity.

I recently started working in a company where pressure in the machine is measured with the flow (C). To my surprise they have a good read on the velocity in the machines.

I wonder what physical quantity is being measured, since it is not static or dynamic pressure? Is the measurement just a 'reference value' that translates to a velocity only due to the experience of years working with these machines?

Measuring tube perpendicular to flow (A), against the flow (B) and with flow (C)

$\endgroup$
11
  • $\begingroup$ So how do your calculations look for B and C? $\endgroup$
    – Solar Mike
    Commented Jul 7, 2022 at 8:51
  • $\begingroup$ The pitot tube formula (as I know it) is $v^2 = 2*\Delta P / \rho$. When both the static (A) and dynamic pressure (B) are know the delta P is the difference between the two. How the velocity would be calculated using (C) is basically my question, so I cannot really answer that. $\endgroup$
    – Twon
    Commented Jul 7, 2022 at 8:58
  • $\begingroup$ So work it out for B and C, Not A. How do the results differ? $\endgroup$
    – Solar Mike
    Commented Jul 7, 2022 at 8:59
  • $\begingroup$ We currently do not have measurements of all these quantities on the same system. I am trying to set that up to prove to my colleagues that these are not the same thing. I am just trying to understand what physical quantity they have been measuring all this time when using (C). $\endgroup$
    – Twon
    Commented Jul 7, 2022 at 9:01
  • $\begingroup$ So base it on the theory - many many textbooks cover pitot tubes. $\endgroup$
    – Solar Mike
    Commented Jul 7, 2022 at 9:02

2 Answers 2

0
$\begingroup$

The C section is reading the suction. Varying between zero for no velocity to -1 atm for maximum speed which has been calibrated to their range of the experiments. The readings will rang between 1 atm for zero flow to zero atm for the calibrated max flow velocity.

Because the lab has a controlled air temperature and pressure the static pressure is constant and doesn't need measurements.

$\endgroup$
0
$\begingroup$

Even with the Pitot tube pointing downstream, there's still a streamline joining a zero-velocity location in the tube opening to a location at the full free-stream velocity, so you can still apply Bernoulli's equation to get the velocity from the pressure difference. I think with the tube this way round, I'd be somewhat worried that said streamline might have to cross from inside to outside the turbulent wake of the tube, thus traversing a region where the flow is not irrotational, and therefore Bernoulli's equation doesn't hold; but if you've observed empirically that the velocity values you get are good, I guess that's not a problem.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.