Help me in determining the right solution in this problem. I already have an initial solution here but when I compute, my answer does not match to the answer key. I would like to know where did I create a mistake. (By the way, this is not a homework.)
These are my initial equations:
Knowing that member BC is a two force member and it is a duplicate so I arrive to this equation. I dismember the member BC and pin J from the body.
$\sum M_J = 2F_{BC}(\frac{80}{80\sqrt(17)})(60) + 2F_{BC}(\frac{320}{80\sqrt(17)})(440) - 2000(200) = 0$
After I solve the force in member BC, I use that value to solve $F_{Ky}$. I dismember the member HL and member BC from the body.
$\sum M_H = -2000(1700) + F_{Ky}(1100) + 2F_{BC}(\frac{320}{80\sqrt(17)})(280) + 2F_{BC}(\frac{80}{80\sqrt(17)})(1440) = 0$
I got a value of around 2500 N but the answer key states that the answer is around 403 N. I am thinking that the condition that HL is connected to the truck can affect in the computation.