Timeline for Direction of tube when measuring air flow
Current License: CC BY-SA 4.0
23 events
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Aug 26 at 13:08 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
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Aug 7, 2022 at 8:10 | answer | added | user28774 | timeline score: 0 | |
Aug 7, 2022 at 5:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Jul 7, 2022 at 22:27 | answer | added | kamran | timeline score: 0 | |
Jul 7, 2022 at 18:49 | comment | added | Tiger Guy | Are they getting good readings or just readings? Installing it backwards would give you a negative flow reading (?), I'd expect pressure at C to be less than A. Their method is counter to how the equation is derived. | |
Jul 7, 2022 at 14:12 | comment | added | Sina Atalay | I am not sure but I suspect Setup C will measure both the dynamic and static pressures as Setup B would do. The main assumptions are that there is no flow at the entrance of the tube and the total mechanical energy is conserved. I think these assumptions are valid for Setup C too. | |
Jul 7, 2022 at 9:19 | comment | added | Solar Mike | As I suggested it may be more sensible to analyze it BEFORE you do the experiments. Pencil and paper are cheap, the experimentation time can be very expensive especially in wind tunnels. Spent hours with sub and supersonic at Uni running labs. | |
Jul 7, 2022 at 9:07 | comment | added | Twon | As I said. The experiment is still being setup. I am trying to find some theory so I can read up on what to expect and/or explain any results I find. | |
Jul 7, 2022 at 9:04 | comment | added | Solar Mike | So analyze it and see what happens. | |
Jul 7, 2022 at 9:03 | comment | added | Twon | Correct. But every single one of them I have been able to find use setup B. I cannot find setup C anywhere at all, hence my question. Does anyone have any theory on that? | |
Jul 7, 2022 at 9:02 | comment | added | Solar Mike | So base it on the theory - many many textbooks cover pitot tubes. | |
Jul 7, 2022 at 9:01 | comment | added | Twon | We currently do not have measurements of all these quantities on the same system. I am trying to set that up to prove to my colleagues that these are not the same thing. I am just trying to understand what physical quantity they have been measuring all this time when using (C). | |
Jul 7, 2022 at 8:59 | comment | added | Solar Mike | So work it out for B and C, Not A. How do the results differ? | |
Jul 7, 2022 at 8:58 | comment | added | Twon | The pitot tube formula (as I know it) is $v^2 = 2*\Delta P / \rho$. When both the static (A) and dynamic pressure (B) are know the delta P is the difference between the two. How the velocity would be calculated using (C) is basically my question, so I cannot really answer that. | |
Jul 7, 2022 at 8:51 | comment | added | Solar Mike | So how do your calculations look for B and C? | |
S Jul 7, 2022 at 8:39 | review | First questions | |||
Jul 7, 2022 at 10:02 | |||||
S Jul 7, 2022 at 8:39 | history | asked | Twon | CC BY-SA 4.0 |