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$\tau = \dfrac{V}{Ib}\int ydA = \dfrac{VQ}{Ib}$

The static/first moment of area, $Q = \int ydA$$Q = \int y dA$, is a property of a shape, and itwhich is always positive.

enter image description here

However, depending on the direction of shear force, $V$, the resulting shear stress can be negative, for which the negative sign indicates the location of a section cut along the span of the beam, and on which face of the section cut the shear stress is acting on/calculated. The sketch below shows where negative shear force occurs, and what negative shear stress means.

enter image description here

$\tau = \dfrac{V}{Ib}\int ydA = \dfrac{VQ}{Ib}$

The static/first moment of area, $Q = \int ydA$, is a property of a shape, and it is always positive.

enter image description here

$\tau = \dfrac{V}{Ib}\int ydA = \dfrac{VQ}{Ib}$

The static/first moment of area, $Q = \int y dA$, is a property of a shape, which is always positive.

enter image description here

However, depending on the direction of shear force, $V$, the resulting shear stress can be negative, for which the negative sign indicates the location of a section cut along the span of the beam, and on which face of the section cut the shear stress is acting on/calculated. The sketch below shows where negative shear force occurs, and what negative shear stress means.

enter image description here

Source Link
r13
  • 8.2k
  • 3
  • 9
  • 28

$\tau = \dfrac{V}{Ib}\int ydA = \dfrac{VQ}{Ib}$

The static/first moment of area, $Q = \int ydA$, is a property of a shape, and it is always positive.

enter image description here