Timeline for Maximum deflection in the beam
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 16, 2022 at 15:52 | vote | accept | Harshit Rajput | ||
| Mar 15, 2022 at 9:42 | history | edited | Harshit Rajput | CC BY-SA 4.0 |
deleted 1788 characters in body
|
| Mar 15, 2022 at 9:41 | answer | added | Harshit Rajput | timeline score: 2 | |
| Mar 15, 2022 at 5:03 | history | edited | Harshit Rajput | CC BY-SA 4.0 |
added 1828 characters in body
|
| Mar 15, 2022 at 3:36 | comment | added | Harshit Rajput | @Chemomechanics I thought a little, and this is what I have - If I differentiate the first equation and equate it to 0, I get a value of x, if that value of x lies between 0 to a, then that result is feasible. If the value is -ve or >a then the result is not feasible. I can repeat the same process with the second equation, to see if the value of x that I get is feasible or not. Does that seem right? | |
| Mar 14, 2022 at 20:26 | comment | added | Chemomechanics | If you encounter an ambiguity, try to push through and investigate it rather than stopping. What do you get when you solve $\frac{dv}{dx}=0$ for the two intervals? Plot the deflection; where does the maximum deflection appear? What conclusions can you draw? | |
| Mar 14, 2022 at 15:55 | comment | added | Harshit Rajput | To make it clear, I'm not talking about the deflection under the load, but the maximum deflection. | |
| Mar 14, 2022 at 15:35 | comment | added | Harshit Rajput | It's not making sense to me, how can we determine a deflection which is in the portion 0<x<a, using the equation which is valid for a<x<L ? | |
| Mar 14, 2022 at 14:38 | comment | added | r13 | Why confused? Both will give the identical result, but the first equation is easier to work with, thus less likely to make mistakes. | |
| Mar 14, 2022 at 12:17 | comment | added | Solar Mike | Either should give the same deflection unless the beam is discontinuous at that point. | |
| Mar 14, 2022 at 11:18 | history | asked | Harshit Rajput | CC BY-SA 4.0 |