Timeline for How to visualize angle of projection in Oblique Parallel Projection?
Current License: CC BY-SA 4.0
20 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 15, 2021 at 2:28 | vote | accept | S. M. | ||
| Dec 6, 2021 at 18:22 | comment | added | S. M. | you could take any cube position, It's not mandatory . Necessary is levelling the the angle $\alpha, \phi$. Please help me to understand. | |
| Dec 6, 2021 at 18:08 | comment | added | NMech | Το be honest I am not sure what is it that you are after in the image. I understand that you want to see the 12 edges of a cube, but I am not sure the camera position, or the cube position and size. | |
| Dec 6, 2021 at 16:37 | comment | added | S. M. | still I am waiting for your image. | |
| Dec 6, 2021 at 8:30 | comment | added | S. M. | I want to see 12 edges of original image projected to view plane with projected and angle $\alpha, \phi$ | |
| Dec 6, 2021 at 7:20 | comment | added | S. M. | could I ask when you provide the full image of projection with projector with angle? | |
| Dec 5, 2021 at 16:57 | history | edited | NMech | CC BY-SA 4.0 |
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| Dec 5, 2021 at 14:53 | comment | added | NMech | It's a similar process to the above. I'm finding the able between the in plane vector and the unit vector of the X axis. | |
| Dec 5, 2021 at 14:45 | comment | added | S. M. | How you got $$e_{out} \cdot e_{plane} = \frac{1}{\sqrt{(x-x_p)^2+ (y-y_p)^2 + 0^2}}\begin{bmatrix} x-x_p\\ y-y_p\\ 0\end{bmatrix}\cdot \begin{bmatrix} 1\\ 0\\ 0\end{bmatrix}$$ in last paragraph and why you multiplying with \begin{bmatrix} 1\\ 0\\ 0\end{bmatrix}? | |
| S Dec 5, 2021 at 14:25 | history | suggested | S. M. | CC BY-SA 4.0 |
I write alpha instead of phi
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| Dec 5, 2021 at 14:23 | review | Suggested edits | |||
| S Dec 5, 2021 at 14:25 | |||||
| Dec 5, 2021 at 14:12 | comment | added | NMech | The "out of plane" refers to the vector which does not exists within the plane you see in the image. It is the vector connecting $(x,y,z)$ to $(x_p, y_p)$. The plane vector is the one connecting $(x,y) $ to $(x_p, y_p)$. | |
| Dec 5, 2021 at 14:09 | history | edited | NMech | CC BY-SA 4.0 |
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| Dec 5, 2021 at 14:00 | comment | added | S. M. | the out of plane vector" mean and why z is present here? – | |
| S Dec 5, 2021 at 13:43 | history | suggested | S. M. | CC BY-SA 4.0 |
I just change bracket.
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| Dec 5, 2021 at 9:42 | review | Suggested edits | |||
| S Dec 5, 2021 at 13:43 | |||||
| Dec 5, 2021 at 9:01 | comment | added | S. M. | OK thank you.. Please do it as soon as possible. | |
| Dec 5, 2021 at 8:59 | comment | added | NMech | apologies, instead of $\phi$ I should have written $a$. I will correct it later, since I am out on a family excursion. | |
| Dec 5, 2021 at 8:57 | comment | added | S. M. | could you show the image with projection and after projection with Projector and angle $\alpha$ and $\phi$, by which I can understand easily. | |
| Dec 5, 2021 at 7:47 | history | answered | NMech | CC BY-SA 4.0 |