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Feb 14, 2021 at 8:02 vote accept ayr
Feb 8, 2021 at 10:18 comment added abc1455 This is applicable anywhere the hessian is invertible. However, you have to take care because it might be that the hessian is not invertible at your extremum e.g.$x^4$, even though it is invertible in the neighborhood of $x=0$
Feb 8, 2021 at 10:14 comment added ayr And in any small neighborhood of this point, where the Hessian $\frac{df}{dx}≠0$ , such control is applicable, I understand correctly?
Feb 8, 2021 at 10:12 review First posts
Feb 8, 2021 at 10:19
Feb 8, 2021 at 10:08 history answered abc1455 CC BY-SA 4.0