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$ 100- 25cos (20) = 76.5076 $

Force in member ob.

We divide the tributory of 75 N by this to get the cos(b-a) 75/ 76.5076 = 0.98029

Arccos (0.98029)= 11.3934

This added to 20 is angle beta.

Beta = 20 + 11.3934 = 31.3934

And Omega = 180- 31.3934= 148.606

Sum of angle in a triangle =180° Omega=180-(70+31.394)

$ 100- 25cos (20) = 76.5076 $

Force in member ob.

We divide the tributory of 75 N by this to get the cos(b-a) 75/ 76.5076 = 0.98029

Arccos (0.98029)= 11.3934

This added to 20 is angle beta.

Beta = 20 + 11.3934 = 31.3934

And Omega = 180- 31.3934= 148.606

$ 100- 25cos (20) = 76.5076 $

Force in member ob.

We divide the tributory of 75 N by this to get the cos(b-a) 75/ 76.5076 = 0.98029

Arccos (0.98029)= 11.3934

This added to 20 is angle beta.

Beta = 20 + 11.3934 = 31.3934

And Omega = 180- 31.3934= 148.606

Sum of angle in a triangle =180° Omega=180-(70+31.394)

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$ 100- 25cos (20) = 76.5076 $

Force in member ob.

We divide the tributory of 75 N by this to get the cos(b-a) 75/ 76.5076 = 0.98029

Arccos (0.98029)= 11.3934

This added to 20 is angle beta.

Beta = 20 + 11.3934 = 31.3934

And Omega = 180- 31.3934= 148.606