Timeline for Calculating Load Inertia in a Leadscrew System
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Feb 7, 2019 at 19:42 | comment | added | crxguy52 | @ConjuringFrictionForces is correct, but he missed a step when he converted form linear acceleration to rotation acceleration. Linear acceleration is m/s^2, angular acceleration is rad/sec^2. Therefore, $$a = \dfrac{L}{2\pi}\dfrac{d^2\theta}{dt^2}$$ Since pitch is distance/rev, this converts lead to distance/radian The equivalent inertia is then $$J = (\dfrac{L}{2\pi})^2m$$ The link in his post supports my case. | |
| Feb 6, 2019 at 22:38 | comment | added | ConjuringFrictionForces | @crxguy52 Good catch. I made an edit in response to your comment. | |
| Feb 6, 2019 at 22:38 | history | edited | ConjuringFrictionForces | CC BY-SA 4.0 |
Missing 2\pi in the derivation. Fixed in response to comment. Edit makes my formula identical to OP's.
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| Oct 12, 2018 at 18:44 | review | Suggested edits | |||
| Oct 12, 2018 at 20:34 | |||||
| Feb 2, 2017 at 13:05 | comment | added | DaveS | I should remember adding references to my equations like you have heh. Now I can't even remember where I got the equation from my question | |
| Feb 2, 2017 at 13:01 | vote | accept | DaveS | ||
| Jan 19, 2017 at 22:03 | review | Late answers | |||
| Jan 19, 2017 at 23:15 | |||||
| Jan 19, 2017 at 21:48 | review | First posts | |||
| Jan 20, 2017 at 1:30 | |||||
| Jan 19, 2017 at 21:47 | history | answered | ConjuringFrictionForces | CC BY-SA 3.0 |