Timeline for Calculating velocity in pipe flow
Current License: CC BY-SA 3.0
17 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 21, 2018 at 23:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 21, 2018 at 22:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 22, 2018 at 21:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jul 23, 2018 at 20:18 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jun 23, 2018 at 19:43 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 24, 2018 at 19:19 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Apr 24, 2018 at 20:09 | comment | added | mart | You have a sixteen fold pressure drop, so your specific volume will drop unless we're talking liauid oxygen ... & thus velocity will increase. There are iterative formulat that take that intop account, I'd jave to hunt them down somewhere. However, that makes the question: Where in your pipe is the velocity you seek? Also, 4 bar pressure, that's less then the inner tube of a racing bike. I don't find 146m/s plausible. | |
| Apr 24, 2018 at 20:08 | comment | added | mart | @jjack OP gets the flow rate from the resistance ($\zeta$), $\zeta$ depends on Re and Re on flow rate ... Only way around interations is a moody chart. Speaking of which, what's the roughness of the pipe? Did you check your math for Re by hand? What temperature (goes into viscosity & density)? | |
| Apr 24, 2018 at 18:22 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Mar 25, 2018 at 18:17 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Feb 23, 2018 at 17:52 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 24, 2018 at 17:31 | answer | added | Justin B. | timeline score: 1 | |
| Nov 19, 2016 at 19:42 | comment | added | jjack | I don't see why you can't insert the equation for Reynolds number and use the viscosity for oxygen. This way there's no iteration. | |
| Nov 16, 2016 at 20:33 | comment | added | JMac | With the information given that seems like the best method. I can't think of any way to solve that with the given info without estimating velocity; and as soon as you do that you're in an iteration loop. | |
| Nov 16, 2016 at 17:41 | comment | added | malleYay | The Point is: I'm not sure if those equations are the applicable ones. I would like to know if there is a straight forward way to calculate turbulent flow through a pipe like there is with laminar flow. | |
| Nov 16, 2016 at 17:22 | comment | added | JMac | If those equations are the applicable ones, it should work. You'll have to make sure it's converging though. You need to find a velocity where the friction losses and Reynolds Number make equivalent equations. For example, your Re = 10175 was gotten by assuming u = 261 m/s. When you use that Re in the Blasius equation, then the pressure drop equation, you get a new velocity. That new velocity would have a new Reynolds number, giving you a new velocity from the Blasius equation/pressure drop formula. This becomes iterative; usually you would want a numerical method to solve this AFAIK. | |
| Nov 16, 2016 at 16:40 | history | asked | malleYay | CC BY-SA 3.0 |