Not sure if I'm applying the formula correctly. I'm trying to find the deflection in a cantilever beam that is loaded by a uniformly-distributed load. The formula is:
$$v=- \frac{wx^2}{24EI}(x^2+6L^2-4Lx) $$
Wherewhere:
$$v =Deflection\\ x=Distance\ from\ wall\\w=3\quad kN/m\\E=200\quad GPa\\I=986e6\quad mm^4\\L=10.5$$$$v = \text{Deflection} \\ x= \text{Distance from wall} \\ w=3\ \text{kN/m} \\ E=200\ \text{GPa} \\ I=986e6\ \text{mm}^4\\ L=10.5\ \text{m}$$
So for x=10.5$x=10.5\ \text{m}$ I'm getting: $$v=- \frac{3000(10.5)^2}{24*200e9*986e6}(10.5^2+6*10.5^2-4*10.5*10.5) $$
$$v=-2.31e-14$$$$v=- \frac{3000(10.5)^2}{24*200e9*986e6}(10.5^2+6*10.5^2-4*10.5*10.5) \\ v=-2.31e-14$$